Difference between revisions of "Sven Bergmann"

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Do you know how to get ''smoothly'' from A to B? Well, you just need to minimize the functional expression
 
Do you know how to get ''smoothly'' from A to B? Well, you just need to minimize the functional expression
<math>\tilde {\cal S}[y(x)] \equiv
+
<math> \tilde {\cal S}[y(x)] \equiv
 
\int_{x_i}^{x_f} \left(\kappa[y(x)]\right)^\nu \, ds(x) =
 
\int_{x_i}^{x_f} \left(\kappa[y(x)]\right)^\nu \, ds(x) =
 
\int_{x_i}^{x_f} {|y''(x)|^\nu \over
 
\int_{x_i}^{x_f} {|y''(x)|^\nu \over

Revision as of 13:41, 8 July 2009

I am the head of the Computational Biology Group (CBG) in the Department of Medical Genetics at the University of Lausanne.


  • Address: Rue de Bugnon 27 - DGM 328 - CH-1005 Lausanne - Switzerland
  • Phone at work: ++41-21-692-5452
  • Cell phone: ++41-78-663-4980
  • http://serverdgm.unil.ch/bergmann
  • e-mail: Sven.Bergmann_AT_unil.ch

Do you know how to get smoothly from A to B? Well, you just need to minimize the functional expression <math> \tilde {\cal S}[y(x)] \equiv \int_{x_i}^{x_f} \left(\kappa[y(x)]\right)^\nu \, ds(x) = \int_{x_i}^{x_f} {|y(x)|^\nu \over

                 \left[1+y'(x)^2\right]^{3\nu-1 \over 2}} \,dx </math>

It turns out that it is possible to find analytically the most general solution <math>y(x)</math>, see this [paper] for details.